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Eurusdd replied Oct 29, 2014Thank you for your contribution. Nice to see you here. I will explain the full proof and idea of the statement shortly. Thanks for your effort though.
The similarity system
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Eurusdd replied Oct 29, 2014We are interested in sequences linearly dependent on n. the sequence x(1)>x(2)>x(4) is not valid because 1-2 is not equal to 2-4. Sequences linearly defined on n makes the theorem powerful.
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Eurusdd replied Oct 29, 2014The true probability is 1, ALMOST SURELY as stated in the proposition. The 97% is for a typical chart platform and the optimal values for k,h
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Eurusdd replied Oct 29, 2014Sure your proof is not correct. Start with a given state and then look at all the branches of the tree coming out of your state. 1 for up and 0 for down. there should be 32 branches. only two will not have those conditions. so probability of 30/32. ...
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Eurusdd replied Oct 29, 2014That post was for a consecutive listed sequence. Corrected
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Eurusdd replied Oct 29, 2014So for 10 consecutive highs if the theorem is not true for the first five, then the probability it is false for the second five also is 0.3%
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Eurusdd replied Oct 29, 2014This is a fantastic result FX-JAY. You are doing well and I must confess, I wish I can just finish what I am doing and get to real trading again. You make me miss the action. Anyway, I am working on the probability for the listed sequence and it is ...
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Eurusdd replied Oct 29, 2014seriously, what is your problem? I don't see a problem. I presented an idea that we can work on and extract something meaningful from it and you here exploding the house... Lol. Park yourself. It's been long since I banned someone. In fact, you will ...
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Eurusdd replied Oct 29, 2014Let him be. Full member of the house. consistent!
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Eurusdd replied Oct 29, 2014Haha, like that. Leave them alone. When we find something substantial later on, they will come running back. I will work on that probability and get back to you.
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Eurusdd replied Oct 29, 2014I will come back in the future with my findings. Thank you all. image
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Eurusdd replied Oct 29, 2014The real reason for submitting this is to find a probabilistic statement for a listed sequence where all sub-sequences in the statement are also listed. If the probability is high enough, game on!!!
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Eurusdd replied Oct 29, 2014I really do not get your problem. This example is for a the case where the sequence is listed and subsequence defined linearly on n. Lol. What is your stress. the application of the theorem or the special case i represented? That is why I stated the ...
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Eurusdd replied Oct 29, 2014The power of the theorem lies in this observation. For a given n, look in the DNA for a set of n^2 distinct real numbers forming some sequence that ends on the current number you are interested in. That is, if we include the current number, we ...
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Eurusdd replied Oct 29, 2014Well I never said something had to be sorted. In fact, I think I posted a revision, using a set for the subsequence so that the problem of sorting out is eliminated. Even in this case, one can make use of it. So, please read what I said carefully.
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Eurusdd replied Oct 29, 2014My version applicable to trading::: image NOTE: The theorem is most powerful if subsequences - in the definition, is defined linearly on n. But in this case I have a problem with a theorem for which there are 22 different proofs.
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Eurusdd replied Oct 29, 2014This theorem is not mine. There are about 22 different proofs of the theorem. If it is true - I cannot say till I prove it myself - then it is the most powerful tool apart from TZ that I have presented here. This theorem means MONEY, if true! The ...
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